XmlSerializer.CanDeserialize(XmlReader) Método

public:
 virtual bool CanDeserialize(System::Xml::XmlReader ^ xmlReader);

public virtual bool CanDeserialize(System.Xml.XmlReader xmlReader);

abstract member CanDeserialize : System.Xml.XmlReader -> bool
override this.CanDeserialize : System.Xml.XmlReader -> bool

Public Overridable Function CanDeserialize (xmlReader As XmlReader) As Boolean

Parâmetros

Retornos

true se isso XmlSerializer puder desserializar o objeto ao qual o XmlReader aponta; caso contrário, false.

Exemplos

O exemplo a seguir chama o CanDeserialize método para verificar se um documento XML pode ser desserializado.

private void TestDocument(string filename, Type objType)
{
    // Using a FileStream, create an XmlTextReader.
    Stream fs = new FileStream(filename, FileMode.Open);
    XmlReader reader = new XmlTextReader(fs);
    XmlSerializer serializer = new XmlSerializer(objType);
    if (serializer.CanDeserialize(reader))
    {
        Object o = serializer.Deserialize(reader);
    }
    fs.Close();
}

Private Sub TestDocument _
                (ByVal filename As String, _
                 ByVal objType As Type)
    ' Using a FileStream, create an XmlTextReader.
    Dim fs As New FileStream(filename, FileMode.Open)
    Dim reader As New XmlTextReader(fs)
    Dim serializer As New XmlSerializer(objType)
    If serializer.CanDeserialize(reader) Then
        Dim o As Object = serializer.Deserialize(reader)
    End If
    fs.Close()
End Sub

Confira também

• Deserialize(Stream)